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Of course, this request has nothing to do with XF.
I am looking for a query with which I can find users with whom I have in common - and - who have in common with me.
These successes are based on the scheme:
User X gives an answer (user_answer_id), but only accepts users whose user_answer_id matches those allowed by user X to answer (accepted_answer_id).
Only users with which I have in common are output. So far so good.
Now comes another factor. Now I know that the users match...
Read more
ادامه مطلب...
I am looking for a query with which I can find users with whom I have in common - and - who have in common with me.
These successes are based on the scheme:
User X gives an answer (user_answer_id), but only accepts users whose user_answer_id matches those allowed by user X to answer (accepted_answer_id).
Only users with which I have in common are output. So far so good.
Now comes another factor. Now I know that the users match...
Read more
ادامه مطلب...